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Lean.Meta.Tactic.Simp.Rewrite

Helper type for implementing discharge?'

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    def Lean.Meta.Simp.discharge?' (thmId : Origin) (x type : Expr) :

    Wrapper for invoking discharge? method. It checks for maximum discharge depth, create trace nodes, and ensure the generated proof was successfully assigned to x.

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            def Lean.Meta.Simp.rewrite? (e : Expr) (s : SimpTheoremTree) (erased : PHashSet Origin) (tag : String) (rflOnly : Bool) :

            Remark: the parameter tag is used for creating trace messages. It is irrelevant otherwise.

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                  Given a match-application e with MatcherInfo info, return some result if at least of one of the discriminants has been simplified.

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                    def Lean.Meta.Simp.simpMatchCore (matcherName : Name) (e : Expr) :
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                                Discharge procedure for the ground/symbolic evaluator.

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                                  Try to unfold ground term in the ground/symbolic evaluator.

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                                      Invoke ground/symbolic evaluator from simp. It uses the seval theorems and simprocs.

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                                        Try to unfold ground term in the ground/symbolic evaluator.

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                                          Return true if e is of the form (x : α) → ... → s = t → ... → False

                                          Recall that this kind of proposition is generated by Lean when creating equations for functions and match-expressions with overlapping cases. Example: the following match-expression has overlapping cases.

                                          def f (x y : Nat) :=
                                            match x, y with
                                            | Nat.succ n, Nat.succ m => ...
                                            | _, _ => 0
                                          

                                          The second equation is of the form

                                          (x y : Nat) → ((n m : Nat) → x = Nat.succ n → y = Nat.succ m → False) → f x y = 0
                                          

                                          The hypothesis (n m : Nat) → x = Nat.succ n → y = Nat.succ m → False is essentially saying the first case is not applicable.

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                                            Tries to solve e using unifyEq?. It assumes that isEqnThmHypothesis e is true.

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                                              Discharges assumptions of the form ∀ …, a = b using rfl. This is particularly useful for higher order assumptions of the form ∀ …, e = ?g x y to instantiate a parameter g even if that does not appear on the lhs of the rule.

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                                                  def Lean.Meta.Simp.mkMethods (s : SimprocsArray) (discharge? : Discharge) (wellBehavedDischarge : Bool) :
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